When we talk about factoring polynomials, there are several characteristics we need to take into account.

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If There Is No Independent Term

If there is no independent term, we must factor out the common factor. Factoring out the common factor from a sum (or difference) consists of transforming it into a product.

We would apply the distributive property:

Example of Polynomial Factorization Without Independent Term

Factor out the common factor and find the roots.

1

The roots are:   y 

It only has one root because the polynomial has no value that makes it zero. Since is squared, the result will always be a positive number, so it is irreducible.

Double Extraction of Common Factor

1

We factor out and .

Since is now a common factor, we factor out .

The roots are and .

If We Have a Binomial

When we have a binomial, one of the following cases may occur:

Difference of Squares

A difference of squares equals the product of sum and difference.

Examples of Exercises with Difference of Squares:

Factor and find the roots:

1

The roots are and

2

The last term is also a difference of squares, so:

The roots are   and 

Sum of Cubes

Example of Exercise with Sum of Cubes:

Difference of Cubes

Example of Exercise with Difference of Cubes:

If We Have a Trinomial

When we have a trinomial, one of the following cases may occur:

Perfect Square Trinomial

A perfect square trinomial equals a binomial squared.

Examples of Perfect Square Trinomials

Factor and find the roots:

1 Estructura de un binomio al cuadrado grafica

We have to ask ourselves:

  • What number squared gives ? The answer is .
  • What number squared gives ? The answer is .

And we have to verify that

The root is , and it is called a double root.

2 estructura de un binomio elevando al cuadrado dibujo

  • What number squared gives ?
  • What number squared gives ?

And we have to verify that

The double root is .

Quadratic Trinomial

To factor the quadratic trinomial , we set it equal to zero and solve the quadratic equation.

If the solutions to the equation are y , the factored polynomial will be:

Examples of Quadratic Trinomials

Factor and find the roots

1

x25x+6x^{2}-5x+6

We set the trinomial equal to zero:

We apply the quadratic formula:

Aplicación de la formula general para ecuaciones de segundo grado

We factor

x25x+6=(x2)(x3)x^{2}-5x+6=(x-2)\cdot (x-3)

The roots are and .

2

x2x6x^{2}-x-6

We set the trinomial equal to zero:

We solve the equation:

Aplicacion de la formula general para ecuaciones de 2do grado

We factor:

x2x6=(x+2)(x3)x^{2}-x-6=(x+2)\cdot (x-3)

The roots are and .

Fourth-Degree Trinomials with Even Exponents

To find the roots, we set it equal to zero and solve the biquadratic equation.

Examples of Fourth-Degree Trinomials with Even Exponents

1

We set the polynomial equal to zero:

x410x2+9=0x^{4} - 10x^{2} + 9 = 0

We make a substitution:

We solve the quadratic equation:

Aplicación de la formula general a una ecuación con cambio de variable

We undo the substitution and obtain the roots:

2

We set the polynomial equal to zero:

We make a substitution:

We solve the quadratic equation:

Uso de la formula general para ecuaciones de segundo grado

We undo the substitution and obtain the roots:

has no real roots, since there is no number that squared is negative.

It factors as

Factorization of a Polynomial of Degree Greater Than Two

We use the remainder theorem and Ruffini's rule to find the integer roots.

The steps to follow are shown with the polynomial:

We take the divisors of the independent term: .

Applying the remainder theorem, we will know for which values the division is exact.

We divide using Ruffini.

Método de ruffini para dividir

Since the division is exact,

One root is .

We continue performing the same operations to find the second factor.

We try again because the first factor could be squared.

División usando el método de Ruffini

Another root is .

The third factor can be found by applying the quadratic equation or as we have been doing, although it has the disadvantage that we can only find integer roots.

We discard and continue testing with .

División usando Ruffini

We factor out from the last binomial and find a rational root.

The factorization of the polynomial is:

Rational Roots

It may happen that the polynomial has no integer roots and only has rational roots. In this case, we take the divisors of the independent term divided by the divisors of the highest degree term, and apply the remainder theorem and Ruffini's rule.

We try:

.

Primera división de Ruffini

We factor:

We try again for:

We try for:

Segunda división de Ruffini

We factor:

We factor out from the third factor.

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Agostina Babbo

Agostina Babbo is an English and Italian to Spanish translator and writer, specializing in product localization, legal content for tech, and team sports—particularly handball and e-sports. With a degree in Public Translation from the University of Buenos Aires and a Master's in Translation and New Technologies from ISTRAD/Universidad de Madrid, she brings both linguistic expertise and technical insight to her work.