Welcome to the exercises on variance, mean deviation, and standard deviation! In this series of exercises, we will explore fundamental concepts in statistics that will help us understand the dispersion and variability of a data set.

Variance, mean deviation, and standard deviation are statistical measures that allow us to quantify the dispersion or variability of a data set with respect to its mean. These measures are especially useful for understanding how dispersed or grouped the values of a data set are and how they are distributed around their central value.

Get ready to strengthen your skills in statistics and discover the fascinating world of data analysis. Let's get started!

1

Find the mean deviation, the variance, and the standard deviation of .

Solution

1 We compute the mean for the series of numbers , with n=5=N. We have the following computations.

 

 

 

2 We compute the value of the mean deviation.

 

 

 

3 Now, we compute the value of the variance.

 

 

4 And finally, we compute the value of the standard deviation.

 

 

2

Find the mean deviation, the variance, and the standard deviation of the following series of numbers:

a .

b .

Solution

a For the series of numbers with we have the following calculations:

For the mean deviation, we first need to compute the mean.

 



We compute the value of the mean deviation.

 



Now, we compute the value of the variance.

 



And finally, we compute the value of the standard deviation.

 

 

b For the series of numbers with , we have the following computations.

For the mean deviation, we first need to compute the mean.

 

 

Then, we compute the value of the mean deviation.

 

 

Now, we compute the value of the variance.

 

 

And finally, we compute the value of the standard deviation.

 

3

Find the variance and the standard deviation of .

Solution

1 We build the frequency table and include the product of the variable by its absolute frequency to compute the mean, and the product of the squared variable by its absolute frequency to compute the variance and the standard deviation.

531575
621272
721498
8216128
9327243
10220200
13113169
15117985

2 We compute the arithmetic mean.

 

3 We compute the variance.

 

4 We compute the standard deviation.

4

A pediatrician obtained the following table about the age (in months) of 50 children from their practice at the time they walked for the first time. Compute the variance.

MonthsChildren
91
104
119
1216
1311
148
151

Solution

We complete the table with:

 

1 The product of the variable by its absolute frequency to compute the mean.

 

2 The product of the squared variable by its absolute frequency to compute the variance and the standard deviation.

91981
10440400
119991089
12161922304
13111431859
1481121568
15115225
506107526

Review these concepts with our math tutor.

 

We compute the arithmetic mean.

 

We compute the variance.

5

The result of rolling two dice 120 times is given by the table. Compute the variance.

SumsTimes
23
38
49
511
620
719
816
913
1011
116
124

Solution

1 We add the columns

x_if_ix_i * f_ix_i^2 * f_i
23612
382472
4936144
51155275
620120720
719133931
8161281024
9131171053
10111101100
11666726
12448576
1208436633

2 We compute the arithmetic mean.

 

 

3 We compute the variance.

 

6

Compute the variance of a statistical distribution given by the following table.

 
[10, 15)3
[15, 20)5
[20, 25)7
[25, 30)4
[30, 35)2

Solution

1 We add the columns

 
[10, 15)12.5337.5468.75
[15, 20)17.5587.51,531.25
[20, 25)22.57157.53,543.75
[25, 30)27.541103,025
[30, 35) 32.52652,112.5
21457.510,681.25

2 We compute the mean.

 

 

3 We compute the variance.

 

7

Compute the variance of the distribution in the table.

 
[10, 20)15115225
[20, 30)2582005,000
[30, 40)351035012,250
[40, 50)45940518,225
[50, 60)55844024,200
[60, 70)65426016,900
[70, 80)75215011,250
421,82088,050

Solution

1 We compute the mean.

 

2 We compute the variance.

 

8

The heights of the players on a basketball team are given by the table. Compute the variance.

HeightNumber of Players
[5.6ft, 5.7ft)1
[5.7ft, 5.9ft)3
[5.9ft, 6.1ft)4
[6.1ft, 6.2ft)8
[6.2ft, 6.4ft)5
[6.4ft, 6.6ft)2

Solution

1 We complete the table with the columns

 
[5.6ft, 5.7ft)5.7ft115.7ft9.8ft
[5.7ft, 5.9ft)5.8ft3417.5ft31ft
[5.9ft, 6.1ft)6ft4824ft43.7ft
[6.1ft, 6.2ft)6.2ft81649.2ft92.3ft
[6.2ft, 6.4ft)6.3ft52131.6ft60.8ft
[6.4ft, 6.6ft)6.5ft22313ft25.6ft
23140.8ft263.2ft

2 We compute the mean.

 

 

3 We compute the variance.

 

9

Given the statistical distribution, compute the variance.

 
[0, 5)3
[5, 10)5
[10, 15)7
[15, 20)8
[20, 25)2
[25, ∞)6

Solution

1 We complete the table with the columns

 
[0, 5)2.533
[5, 10)7.558
[10, 15)12.5715
[15, 20)17.5823
[20, 25)22.5225
[25, )631
31

2 It is not possible to compute the mean, because it is not possible to find the class midpoint of the last interval.

 

3 If there is no mean, it is not possible to compute the variance.

10

Consider the following data: . Then:

 

a Compute its mean and its variance.

b If we multiply all the previous data by , what will the new mean and variance be?

Solution

We complete the table with the column

24
39
416
636
864
10100
33229

1 Mean and variance:

 

 

 

2 If all the values of the variable are multiplied by a number, the mean is multiplied by and the variance is multiplied by the square of that number.

 

 

Summarize with AI:

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Agostina Babbo

Agostina Babbo is an English and Italian to Spanish translator and writer, specializing in product localization, legal content for tech, and team sports—particularly handball and e-sports. With a degree in Public Translation from the University of Buenos Aires and a Master's in Translation and New Technologies from ISTRAD/Universidad de Madrid, she brings both linguistic expertise and technical insight to her work.