Statistics is a fundamental tool for analyzing and interpreting data across various disciplines, from social sciences to engineering. Understanding statistical concepts and knowing how to apply them correctly is crucial for making informed decisions based on data.

This section of solved exercises is designed to help consolidate the theoretical knowledge acquired in statistics topics. Through practice with real problems, the goal is to develop analytical skills and strengthen the ability to solve common and complex statistical situations.

1

Indicate which variables are qualitative and which are quantitative

  • Favorite food.
  • Career you like.
  • Number of goals scored by your favorite team in the last season.
  • Number of students in your school.
  • Eye color of your classmates.
  • Intelligence coefficient of your classmates.
Solution
  • Favorite food. Qualitative
  • Profession you like. Qualitative
  • Number of goals scored by your favorite team in the last season. Quantitative
  • Number of students in your school. Quantitative
  • Eye color of your classmates. Qualitative
  • Intelligence coefficient of your classmates. Quantitative
2

Indicate which of the following variables are discrete and which are continuous:

  • Number of shares sold each day on the stock exchange.
  • Temperatures recorded each hour at an observatory.
  • Duration period of a car.
  • The diameter of the wheels of several cars.
  • Number of children in 50 families.
  • Annual census of American people.
Solution
  • Number of shares sold each day on the stock exchange. Discrete
  • Temperatures recorded each hour at an observatory. Continuous
  • Duration period of a car. Continuous
  • The diameter of the wheels of several cars. Continuous
  • Number of children in 50 families. Discrete
  • Annual census of American people. Discrete
3

Classify the following variables as qualitative or quantitative, and as discrete or continuous:

  • The nationality of a person.
  • Number of gallons of water contained in a tank.
  • Number of books on a bookshelf.
  • Sum of points obtained when rolling a pair of dice.
  • The profession of a person.
  • The area of the different tiles of a building.
Solution
  • The nationality of a person. Qualitative
  • Number of gallons of water contained in a tank. Quantitative and continuous
  • Number of books on a bookshelf. Quantitative and discrete
  • Sum of points obtained when rolling a pair of dice. Quantitative and discrete
  • The profession of a person. Qualitative
  • The area of the different tiles of a building. Quantitative and continuous
4

The scores obtained by a group on a test were:

Construct the frequency distribution table and draw the frequency polygon.

Solution

ValueTallyFrequencyCumulative FrequencyRelative FrequencyCumulative Relative Frequency
13III330.150.15
14I140.050.20
15V590.250.45
16IIII4130.200.65
18III3160.150.80
19I1170.050.85
20II2190.100.95
22I1200.051
20

In the fourth column we place the cumulative frequency .

In the first cell we place the first absolute frequency. In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

In the fifth column we place the relative frequencies , which are the result of dividing each absolute frequency by .

In the sixth column we place the cumulative relative frequency .

In the first cell we place the first relative frequency. In the second cell we add the value of the previous cumulative relative frequency plus the corresponding cumulative relative frequency, and so on until the last, which must be equal to .

Frequency Polygon

On the x-axis are the data values and on the y-axis are the absolute frequencies.

Polígono de frecuencias representacion grafica

5

The number of stars of the hotels in a city is given by the following series:

Construct the frequency distribution table and draw the bar diagram.

Solution

Steps to construct the frequency distribution table and draw the bar diagram:

ValueTallyFrequencyCumulative FrequencyRelative FrequencyCumulative Relative Frequency
1VI660.1580.158
2XII12180.3160.474
3XVI16340.4210.895
4IIII4380.1051
381

In the fourth column we place the cumulative frequency .

In the first cell we place the first absolute frequency. In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

In the fifth column we place the relative frequencies () which are the result of dividing each absolute frequency by .

In the sixth column we place the cumulative relative frequency .

In the first cell we place the first relative frequency. In the second cell we add the value of the previous cumulative relative frequency plus the corresponding cumulative relative frequency, and so on until the last, which must be equal to .

Bar Diagram

On the x-axis are the data values and on the y-axis are the absolute frequencies.

 

diagrama Gráfica de barras

6

The grades of 50 students were as follows:

Construct the frequency distribution table and draw the bar diagram.

Solution

Steps to construct the frequency distribution table and draw the bar diagram:

ValueFrequencyCumulative FrequencyRelative FrequencyCumulative Relative Frequency
0110.020.02
1120.020.04
2240.040.08
3370.060.14
46130.120.26
511240.220.48
612360.240.72
77430.140.86
84470.080.94
92490.040.98
101500.021.0
501

 

In the fourth column we place the cumulative frequency .

In the first cell we place the first absolute frequency. In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

In the fifth column we place the relative frequencies () which are the result of dividing each absolute frequency by .

In the sixth column we place the cumulative relative frequency .

In the first cell we place the first relative frequency. In the second cell we add the value of the previous cumulative relative frequency plus the corresponding cumulative relative frequency, and so on until the last, which must be equal to .

Bar Diagram

On the x-axis are the data values and on the y-axis are the absolute frequencies.

 

Gráfica de barras

7

The weights of 65 employees of a factory are given by the following table:

Weight 
[50, 60)8
[60, 70)10
[70, 80)16
[80, 90)14
[90, 100)10
[100, 110)5
[110, 120)2

  • Construct the frequency table.
  • Draw the histogram and frequency polygon.
Solution
  • Construct the frequency table:

IntervalValueFrequencyCumulative FrequencyRelative FrequencyCumulative Relative Frequency
[50, 60)55880.120.12
[60, 70)6510180.150.27
[70, 80)7516340.240.51
[80, 90)8514480.220.73
[90, 100)9510580.150.88
[100, 110)1055630.080.96
[110, 120)1152650.030.99
65

In the fourth column we place the cumulative frequency .

In the first cell we place the first absolute frequency. In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

In the fifth column we place the relative frequencies () which are the result of dividing each absolute frequency by .

In the sixth column we place the cumulative relative frequency .

In the first cell we place the first relative frequency. In the second cell we add the value of the previous cumulative relative frequency plus the corresponding cumulative relative frequency, and so on until the last, which must be equal to .

b. Draw the histogram and frequency polygon.

Histogram

The frequency polygon is constructed by connecting the midpoints of each rectangle.

 

Histograma y poligono de frecuencias

8

The 40 students in a class obtained the following scores out of 50 on a Physics exam:

  • Construct the frequency table.
  • Draw the histogram and frequency polygon.
Solution
  • Construct the frequency table:

IntervalValueFrequencyCumulative FrequencyRelative FrequencyCumulative Relative Frequency
[0, 5)2.5110.0250.025
[5, 10)7.5120.0250.050
[10, 15)12.5350.0750.125
[15, 20)17.5380.0750.200
[20, 25)22.53110.0750.275
[25, 30)27.56170.1500.425
[30, 35)32.57240.1750.600
[35, 40)37.510340.2500.850
[40, 45)42.54380.1000.950
[45, 50)47.52400.0501.000
401

 

In the fourth column we place the cumulative frequency .

In the first cell we place the first absolute frequency. In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

In the fifth column we place the relative frequencies () which are the result of dividing each absolute frequency by .

In the sixth column we place the cumulative relative frequency .

In the first cell we place the first relative frequency. In the second cell we add the value of the previous cumulative relative frequency plus the corresponding cumulative relative frequency, and so on until the last, which must be equal to .

b. Draw the histogram and frequency polygon.

Histogram

The frequency polygon is constructed by connecting the midpoints of each rectangle.

 

Histograma de frecuencias dibujo

9

Given a statistical distribution that is provided by the following table:

Value Frequency
615
6418
6742
7027
738

 

Calculate:

  • The mode, median, and mean.
  • The range, mean deviation, variance, and standard deviation.
Solution

We complete the table with:

  • The cumulative frequency () to calculate the median
  • The product of the variable by its absolute frequency () to calculate the mean
  • The deviation from the mean and its product by the absolute frequency to calculate the mean deviation
  • The product of the variable squared by its absolute frequency () to calculate the variance and standard deviation

ValueFrequencyCumulative Frequencyfxx - Meanf(x - Mean)fx²
61553056.4532.2518605
64182311523.4562.1073728
67426528140.4518.90188538
70279218902.5568.85132300
7381005845.5544.4042632
1006745226.50455803

Mode

The mode is the value with the highest absolute frequency. Looking at the column with values, the highest absolute frequency is 42, which corresponds to .

Median

To calculate the median, we divide by 2, and we see that the cell with closest to 50 is 65, which corresponds to .

Mean

We calculate the sum of the variable by its absolute frequency (), which is 6745, and divide it by .

Mean Deviation

We calculate the sum of the products of deviations from the mean by their corresponding absolute frequencies , which is 226.5, and divide by .

Range

We find the difference between the largest and smallest values:

Variance

We calculate the sum of , divide it by , and subtract the square of the arithmetic mean .

Standard Deviation

We take the square root of the variance:

10

Calculate the mean, median, and mode of the following series of numbers:

Solution

We create a table with the following columns:

  • The values of the variable ()
  • The absolute frequencies ()
  • The cumulative frequencies () to calculate the median
  • The product of the variable by its absolute frequency () to calculate the mean

ValueFrequencyCumulative Frequencyfx
2224
3246
45920
561530
621712
832024
2096

 

Mode

The mode is the value with the highest absolute frequency. Looking at the column with values, the highest absolute frequency is 6, which corresponds to .

Median

To calculate the median, we divide by 2, and we see that the cell with where 10 appears corresponds to .

Mean

We calculate the sum of the variable by its absolute frequency (), which is 96, and divide it by .

11

Find the variance and standard deviation of the following series of data:

Solution

We calculate the arithmetic mean:

We apply the variance formula:

We take the square root of the variance:

12

Find the mean, median, and mode of the following series of numbers:

Solution

Mode

The mode is 5 because it is the value that appears most frequently.

Median

The series has an even number of values, so the median will be the average of the two central values.

Mean

We apply the mean formula.

13

Find the mean deviation, variance, and standard deviation of the following series of numbers:

1

2

Solution

1

Mean

Mean Deviation

Variance

Standard Deviation

2

Mean

Mean Deviation

Variance

Standard Deviation

14

A test was administered to factory employees, obtaining the following table:

IntervalFrequency
[38, 44)7
[44, 50)8
[50, 56)15
[56, 62)25
[62, 68)18
[68, 74)9
[74, 80)6

 

Draw the histogram and the cumulative frequency polygon.

Solution

We add a new column with the cumulative frequencies ():

In the first cell we place the first absolute frequency.

In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

IntervalFrequencyCumulative Frequency
[38, 44)77
[44, 50)815
[50, 56)1530
[56, 62)2555
[62, 68)1873
[68, 74)982
[74, 80)688
88

 

Histograma y polígono de frecuencias acumuladas

15

Given the statistical series:

Calculate:

  • The mode, median, and mean
  • The mean deviation, variance, and standard deviation
  • Quartiles 1 and 3
  • Deciles 2 and 7
  • Percentiles 32 and 85
Solution

a

Mode

There is no mode because all values have the same frequency.

Median

Ordering the data:

Therefore, the median is:

Mean

Variance

Standard Deviation

Mean Deviation

Range

Quartiles

Deciles

The formula for the position of deciles is:

Therefore, the deciles we are looking for are at positions:

Percentiles

The formula for the position of percentiles is:

Therefore, the percentiles we are looking for are at positions:

 

b 


Mode

There is no mode because all values have the same frequency.

Median

Ordering the data:

Therefore, the median is:

Mean

Variance

Standard Deviation

Mean Deviation

Range

Quartiles

Deciles

The formula for the position of deciles is:

Therefore, the deciles we are looking for are at positions:

Percentiles

The formula for the position of percentiles is:

Therefore, the percentiles we are looking for are at positions:

16

A statistical distribution is given by the following table:

IntervalFrequency
[10, 15)3
[15, 20)5
[20, 25)7
[25, 30)4
[30, 35)2

Calculate:

  • The mode, median, and mean.
  • The range, mean deviation, and variance.
  • Quartiles 1 and 3.
  • Deciles 3 and 6.
  • Percentiles 30 and 70.
Solution

We complete the table with:

  • The cumulative frequency () to calculate the median
  • The product of the variable by its absolute frequency () to calculate the mean
  • The deviation from the mean and its product by the absolute frequency to calculate the mean deviation
  • The product of the variable squared by its absolute frequency () to calculate the variance

Interval FrequencyCumulative Frequencyfxf(x - Mean)²fx²
[10, 15)12.53337.527.857468.75
[15, 20)17.55887.521.4291537.3
[20, 25)22.5715157.553543.8
[25, 30)27.541911022.8573025
[30, 35)32.52216521.4292112.5
21457.598.57110681.25

 

Mode

First, we find the interval where the mode is located, which will be the interval with the highest absolute frequency ().

Modal class:

We apply the formula for calculating the mode for grouped data, extracting the following data:

Lower limit:

Median

We find the interval where the median is located by dividing by 2, since the median is the central value:

We look in the column of cumulative frequencies () for the interval that contains 10.5:

Median class:

We apply the formula for calculating the median for grouped data, extracting the following data:

Mean

We calculate the sum of the variable by its absolute frequency (), which is 457.5, and divide it by :

Range

We find the difference between the largest and smallest values:

Mean Deviation

We calculate the sum of the products of deviations from the mean by their corresponding absolute frequencies , which is 98.571, and divide by :

Variance

We calculate the sum of , divide it by , and subtract the square of the arithmetic mean .

Quartiles

Calculation of the first quartile

We find the interval where the first quartile is located by multiplying 1 by and dividing by 4:

We look in the column of cumulative frequencies () for the interval that contains 5.25:

Class of :

We apply the formula for calculating quartiles for grouped data, extracting the following data:

Calculation of the third quartile

We find the interval where the third quartile is located by multiplying 3 by and dividing by 4:

We look in the column of cumulative frequencies () for the interval that contains 15.75:

Class of :

We apply the formula for calculating quartiles for grouped data, extracting the following data:

Deciles

Calculation of the third decile

We find the interval where the third decile is located by multiplying 3 by and dividing by 10:

We look in the column of cumulative frequencies () for the interval that contains 6.3:

Class of :

We apply the formula for calculating deciles for grouped data, extracting the following data:

Calculation of the sixth decile

We find the interval where the sixth decile is located by multiplying 6 by and dividing by 10:

We look in the column of cumulative frequencies () for the interval that contains 12.6:

Class of :

We apply the formula for calculating deciles for grouped data, extracting the following data:

Percentiles

The 30th percentile is equal to the 3rd decile

Calculation of the 70th percentile

We find the interval where the 70th percentile is located by multiplying 70 by and dividing by 100:

We look in the column of cumulative frequencies () for the interval that contains 14.7:

Class of :

We apply the formula for calculating percentiles for grouped data, extracting the following data:


 

17

Given the statistical distribution:

Interval Frequency
[0, 5)3
[5, 10)5
[10, 15)7
[15, 20)8
[20, 25)2
[25, ∞)6

 

Find:

  • The median and mode.
  • Quartiles 1 and 3.
  • Mean.
Solution

We extend the table with another column where we place the cumulative frequency ():

In the first cell we place the first absolute frequency.

In the second cell we add the value of the previous cumulative frequency plus the corresponding absolute frequency, and so on until the last, which must be equal to .

IntervalValueFrequencyCumulative Frequency
[0, 52.533
[5, 10)7.558
[10, 15)12.5715
[15, 20)17.5823
[20, 25)22.5225
[25, ∞)631
31

 

Mode

First, we find the interval where the mode is located, which will be the interval with the highest absolute frequency ().

Modal class:

We apply the formula for calculating the mode for grouped data, extracting the following data:

Lower limit:

Median

We find the interval where the median is located by dividing by 2, since the median is the central value:

We look in the column of cumulative frequencies () for the interval that contains 15.5:

Median class:

We apply the formula for calculating the median for grouped data, extracting the following data:

Quartiles

Calculation of the first quartile

We find the interval where the first quartile is located by multiplying 1 by and dividing by 4:

We look in the column of cumulative frequencies () for the interval that contains 7.75:

Class of :

We apply the formula for calculating quartiles for grouped data, extracting the following data:

Calculation of the third quartile

We find the interval where the third quartile is located by multiplying 3 by and dividing by 4:

We look in the column of cumulative frequencies () for the interval that contains 23.25:

Class of :

We apply the formula for calculating quartiles for grouped data, extracting the following data:

Mean

The mean cannot be calculated because we cannot determine the class mark of the last interval.

If you want your children to reinforce this subject, or need to reinforce it yourself, don't hesitate to visit Superprof to find elementary school math classes or, if you prefer, an online math teacher.

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Agostina Babbo

Agostina Babbo is an English and Italian to Spanish translator and writer, specializing in product localization, legal content for tech, and team sports—particularly handball and e-sports. With a degree in Public Translation from the University of Buenos Aires and a Master's in Translation and New Technologies from ISTRAD/Universidad de Madrid, she brings both linguistic expertise and technical insight to her work.